0=-16x^2+16x+5

Solution for 0=-16x^2+16x+5 equation:

0=-16x^2+16x+5

We move all terms to the left:

0-(-16x^2+16x+5)=0

We add all the numbers together, and all the variables

-(-16x^2+16x+5)=0

We get rid of parentheses

16x^2-16x-5=0

a = 16; b = -16; c = -5;
Δ = b2-4ac
Δ = -162-4·16·(-5)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-24}{2*16}=\frac{-8}{32}
=-1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+24}{2*16}=\frac{40}{32}
=1+1/4
$